Practice: Algebra (transpose) 22 Algebra (transpose) 1 / 4 Part b) x=y^3 y=x/y x=y^2 Before we get too involved, lets see if we can simplify any other this: let's rewrite it so we can see it better, and then cancel out what we can One last step! We need to transpose the equation to make x the subject! (this is quite unusual!) done! 2 / 4 . . . 3 / 4 Part a) x = 4√(4y^2) x = 3√(4y^2) x = 5√(4y^2) Let's write out the question, we can then collect like terms: Let's cancel what we can, and then rewrite it to make it neater: Multiply both sides by 4y to move it up, and then take the fifth root of both sides: and we are done! 4 / 4 Part a) -13/19 -15/19 -14/19 This is a substitution question, so lets rewrite the exercise with the respective values for each letter: At every step, we should calculate what we can, so it will be simpler to handle: Collect like terms, so we will add 3x to both sides, it's okay to equal zero! Isolate the x term (subtract 15 from both sides), and then we can divide by 19: Your score is LinkedIn Facebook Twitter VKontakte